Harinder Pal Sandhu into the finals of the Victorian Open

SportsCafe Desk
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Indian squash star Harinder Pal Sandhu continued his terrific form cruising into his second consecutive PSA world tour finals at the VIctorian Open after defeating Piedro Schweertman of Netherlands 11-5, 11-8, 11-8. Sandhu won the South Australian Open title which was his third consecutive PSA title

A winner of a PSA title a week back, India's Harinder Pal Sandhu is at the doorsteps of another success having reached the final of the Victorian Open, a PSA world tour event here on Saturday. In the semi-final, he defeated the second seed Piedro Schweertman of Netherlands 11-5, 11-8, 11-8

The third seed Harinder, who has been in good touch has not dropped a game enroute to the final where he will now meet the top seed Rex Hedrick of Australia. As in the earlier matches, fluency marked the Indian's show as he took just 35 minutes to complete the task for a passage to the title-round. He had in comparison beaten Piedro with a degree of difficulty in the previous tournament in Adelaide at the semi-final stage.

Earlier, Sandhu won the South Australian Open title defeating Rhys Dowling 11-8, 12-10, 11-4 in the final.

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